Want to know:
比Shortest Word Distance I 多了一个word1.equals(word2)的条件 for (int i = 0; i < words.length; i++) { if (words[i].equals(word1) || words[i].equals(word2)) { if (index != -1 && (word1.equals(word2) || !words[index].equals(words[i]))) { min = Math.min(i - index, min); } index = i; } }
Get a detailed, AI-powered explanation for this question and thousands more on StudyFetch.
Get the Answer for FreeHow StudyFetch Helps You Master This Topic
AI-Powered Answers
Get instant, detailed explanations powered by AI that understands your course material.
Deep Understanding
Go beyond surface-level answers with step-by-step breakdowns and examples.
Personalized Learning
Spark.E adapts to your learning style and helps you connect ideas.
Practice & Test
Turn any question into flashcards, quizzes, and practice tests to solidify your knowledge.
Explore More Questions
- Quel est le résultat de (3,89 - 9,27)?
- 82: Which of the following rules is less likely to support the concept of least privilege? A.) The number of administrative accounts should be kept to a minimum B.) Administrators should use regular accounts when performing routing operations like reading mail C.) Permissions on tools that are likely to be used by hackers should be as restrictive as possible D.) Only data to and from critical systems and applications should be allowed through the firewall
- A variable subtracted from the left-hand side of a greater-than-or-equal to constraint to convert the constraint into an equality is known as a(n)a.surplus variable.b.slack variable.c.unbounded variable.d.binding constraint.