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Using prices[i] - prices[i - 1] is same to find the maximum subarray int profit = 0;; int max = 0; for (int i = 1; i < prices.length; i++) { if (profit <= 0) { profit = prices[i] - prices[i - 1]; } else { profit += prices[i] - prices[i - 1]; } max = Math.max(max, profit); }
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