Want to know:
120) What is the major difference in the structure of the product formed in a Grignard reaction when an alkyl magnesium halide (Grignard reagent) is reacted with an epoxide rather than an aldehyde or ketone followed by work-up with H3O+?A) The alkyl group from the Grignard reagent will be bonded to the α-carbon of the alcohol product.B) The alkyl group from the Grignard reagent will be bonded to the β-carbon of the alcohol product.C) The alkyl group from the Grignard reagent will form an ether product rather than an alcohol product.D) Two equivalents of the Grignard will result in the bonding of two alkyl groups to the α-carbon of the alcohol product.E) The epoxide will protonate the Grignard reagent resulting an alkane product.
Get a detailed, AI-powered explanation for this question and thousands more on StudyFetch.
Get the Answer for FreeHow StudyFetch Helps You Master This Topic
AI-Powered Answers
Get instant, detailed explanations powered by AI that understands your course material.
Deep Understanding
Go beyond surface-level answers with step-by-step breakdowns and examples.
Personalized Learning
Spark.E adapts to your learning style and helps you connect ideas.
Practice & Test
Turn any question into flashcards, quizzes, and practice tests to solidify your knowledge.
Explore More Questions
- what are common nucleophiles that open the epoxide ring
- more reactive than ethers due to the presence of the larger, more polarizable S atom. Unlike ethers, sulfides will undergo attack on an alkyl halide
- nucleophilic attack on carbonyl carbon, proton transfer, asymmetric ketone gives chirality center (enantiomers)