Want to know:
52) When pent-1-ene is treated with mercury(II) acetate in methanol and the resulting product is reacted with NaBH4, what is the primary organic compound which results?A) 3-ethoxypentaneB) 1-methoxypentaneC) 1-ethoxypentaneD) 2-ethoxypentaneE) 2-methoxypentane
Get a detailed, AI-powered explanation for this question and thousands more on StudyFetch.
Get the Answer for FreeHow StudyFetch Helps You Master This Topic
AI-Powered Answers
Get instant, detailed explanations powered by AI that understands your course material.
Deep Understanding
Go beyond surface-level answers with step-by-step breakdowns and examples.
Personalized Learning
Spark.E adapts to your learning style and helps you connect ideas.
Practice & Test
Turn any question into flashcards, quizzes, and practice tests to solidify your knowledge.
Explore More Questions
- amine attacks carbonyl group, oxygen protonated to remove negative charge, deprotonation gives a carbinolamine (H taken from the N), OH group protonated into a good leaving group, water leaves, C=N double bond forms, intermediate deprotonated to generate enamine
- competing elimination with secondary alkyl halide or tosylate gives poor yields
- Because nucleophiles are also bases, nucleophilic substitution, and base-promoted eliminations are...