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C'est une addition de termes on utilise (u+v)' = u' + v'dérivée de 2x => 2dérivée de 5/3x-2 => on peut poser u(x) = 5 u'(x) = 0 v(x) = 3x-2 v'(x) = 3On utilise la formule (u/v)' = (u'v - uv' )/ v²
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