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It was found for the reaction A<-->B, the forward rate constant (kf) in the absence of enzyme was 1x10^-2/s, whereas the kf in the presence of enzyme was 5x10^6/s.a. Calculate the rate enhancement provided by the enzyme for this chemical reaction.b. If the equilibrium constant (Keq) for the A<-->B reaction is 1x10^3 in the absence of enzyme, what is the Keq in the presence of enzyme? Explain. (ch7)
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